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A HRB 16:00 nos encontramos en situación 35º 50' N, 006º10' W, navegando a 8 nudos al rumbo de aguja = 060º. Declinación magnética = 5º NW. Desvío de la aguja = +5º (más). A HRB 17:00 caemos al rumbo de aguja = 335º, empieza a soplar viento del W, que nos produce un abatimiento de 10º, y entramos en zona de corriente de Rc =090º e Intensidad horaria = 3 millas. Al nuevo rumbo, el desvío de la aguja es 0º. Calcular la situación a HRB 18:30.At ship’s clock 16:00 we are at 35º 50' N, 006º 10' W, sailing at 8 knots on compass course 060º. Variation = 5º NW. Deviation = +5º (plus). At 17:00 we turn to compass course 335º, a westerly starts to blow giving 10º of leeway, and we enter a current setting 090º at 3 miles an hour. On the new course, deviation is 0º. Calculate the position at 18:30.
Show the answer
Correct answer: b) 36º 05.3' N 006º 01.0' W
Why it is correct
First leg: 8 miles at 060º. Second: true 330º, with wind to port 340º, 12 miles. Current: 4.5 miles east. Arrival: 36º 05.3′ N, 006º 01.0′ W.
Why the others are not
- a) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- Find each leg’s course, with leeway if any.
- Break each leg and the current into north-south and east-west, and add them.
- Turn departure into longitude: ΔLong = departure / cos(mean latitude).
Where this question comes from
- Junta de Andalucía · 2016 · 2ª convocatoria · PY Módulo de navegación · question 13 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.