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A HRB = 15h 00m obtenemos simultáneamente demora verdadera al faro de Punta Paloma = 340º y demora verdadera al faro de Punta Cires = 120º. Situados, damos rumbo al puerto de Tánger (luz del espigón), teniendo en cuenta que tenemos viento del Este que nos produce un abatimiento de 20º. Calcular el rumbo de aguja para llegar a Tánger. Declinación magnética = 4º NE y desvío de la aguja = –4º (menos).At HRB 15h 00m you simultaneously obtain Dv Punta Paloma = 340º and Dv Punta Cires = 120º, then head for Tangier port breakwater light with an East wind causing 20º leeway (variation 4º NE, deviation –4º). Find Ra:

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Correct answer: c) 180º

Why it is correct

Intersecting Dv(Paloma) = 340º (reciprocal 160º) and Dv(Cires) = 120º (reciprocal 300º) fixes the vessel at 35º 59.0′ N, 005º 38.0′ W. From there the surface course to Tangier breakwater (35º 47.4′ N, 005º 48.2′ W) is Rs = 200º. With an East wind on the port side (+20º starboard leeway), steer 20º to port: Rv = 200º − 20º = 180º. Since Ct = +4º − 4º = 0º, Ra = 180º.

Why the others are not

  • a) Does not subtract the 20º starboard leeway from the surface course Rs = 200º.
  • b) Does not subtract the 20º starboard leeway from the surface course Rs = 200º.
  • d) Does not subtract the 20º starboard leeway from the surface course Rs = 200º.

How to work it out in the exam

  1. Plot the intersection of Dv(Paloma) = 340º and Dv(Cires) = 120º and measure Rs = 200º to Tangier.
  2. Subtract the 20º starboard leeway (Rv = 180º) and apply Ct = 0º: Ra = 180º.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.