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Navegamos a 8 nudos en zona de corriente de rumbo de corriente = W e intensidad horaria = 3 millas. Al encontrarnos a 3 millas al E verdadero del faro de Punta Almina, damos rumbo a Algeciras (luz roja de la bocana del puerto). Calcular el rumbo de aguja sabiendo que la declinación magnética = 7º NE y el desvío de la aguja = +5º (más).Steaming at 8 knots in a current setting West at Ihc = 3 knots, when 3 miles due East true of Punta Almina lighthouse you head for Algeciras port red entrance light (variation 7º NE, deviation +5º). Find Ra:

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Correct answer: b) 332º

Why it is correct

From 3 miles due East of Punta Almina (35º 54.0′ N, 005º 12.8′ W) to Algeciras red entrance light (36º 07.9′ N, 005º 26.0′ W) the effective course is Ref = 322º. Solving the current triangle with Rc = 270º, Ihc = 3 knots and Vb = 8 knots gives Rv = 344º. With Ct = +7º + 5º = +12º, the compass course is Ra = 344º − 12º = 332º.

Why the others are not

  • a) Does not counteract the west-going current to Rv = 344º or fails to subtract Ct = +12º.
  • c) Does not counteract the west-going current to Rv = 344º or fails to subtract Ct = +12º.
  • d) Does not counteract the west-going current to Rv = 344º or fails to subtract Ct = +12º.

How to work it out in the exam

  1. Plot Ref = 322º from 3′ E of Almina to Algeciras and counteract Rc = 270º (3 kn) with Vb = 8 kn ⇒ Rv = 344º.
  2. Subtract Ct = +7º + 5º = +12º: Ra = 344º − 12º = 332º.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.