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Navegando a Ra= 251º con velocidad de máquina de 12 nudos, a Hrb= 11:00 tomamos una demora de aguja al Faro de Punta Cires de 159º; a Hrb= 11:20 del mismo día tomamos distancia radar al Faro de Isla de Tarifa de 3 millas. El desvío es de 2,0º(E) y la declinación magnética= 1,0º(W). Determinar nuestra situación verdadera a Hrb= 11:20.On Ra = 251º at 12 knots (deviation 2.0º E, variation 1.0º W), Da Punta Cires = 159º at 11:00 and radar distance to Isla de Tarifa = 3 miles at 11:20. Find your true position at 11:20:

Show the answer

Correct answer: b) l = 035º 57.2' N; L = 005º 35.4' W.

Why it is correct

With Ct = −1º + 2º = +1º, true course is Rv = 252º and the 11:00 true bearing to Punta Cires is Dv = 160º. In 20 minutes (11:00 to 11:20) at 12 knots you run 4 miles along 252º; advancing the bearing line 4 miles along 252º to intersect the 3-mile arc from Isla de Tarifa gives l = 35º 57.2′ N, L = 005º 35.4′ W.

Why the others are not

  • a) Does not advance the bearing Dv(Cires) = 160º by 4 miles along 252º to intersect the 3′ arc from Tarifa.
  • c) Does not advance the bearing Dv(Cires) = 160º by 4 miles along 252º to intersect the 3′ arc from Tarifa.
  • d) Does not advance the bearing Dv(Cires) = 160º by 4 miles along 252º to intersect the 3′ arc from Tarifa.

How to work it out in the exam

  1. Compute Ct = +1º, Rv = 252º, Dv(Cires) = 160º and distance run d = 4 miles in 20 min.
  2. Advance the Cires bearing line 4′ along 252º and intersect with the 3′ arc from Tarifa: 35º 57.2′ N, 005º 35.4′ W.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.