Hover or tap underlined Spanish terms to see their translation and exam tip.
El 27 de enero del 2025 el yate Noega parte de la posición l=37º 32` N L=001º 06`W navegando con Rumbo verdadero= 140º CT= -5º, velocidad de máquinas 12 nudos. Calcular analíticamente coordenadas y Rumbo de aguja después de una hora de navegaciónOn 27 January 2025 the yacht Noega leaves l=37º 32` N L=001º 06`W on true course 140º, total correction -5º, engine speed 12 knots. Calculate analytically the position and compass course after one hour’s sailing
Show the answer
Correct answer: c) l=37º 22.8’ N L=000º 56.3’ W Ra= 145º
Why it is correct
d = 12. Δlat = 9.2′ S. Departure = 7.7′ E. ΔLong = 9.7′. Arrival: 37º 22.8′ N, 000º 56.3′ W. Compass = 140º + 5º = 145º.
Why the others are not
- a) It does not match the working.
- b) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- Find the true course and distance.
- Δlat = d × cos R. Departure = d × sin R. ΔLong = departure / cos(mean latitude).
Where this question comes from
- Región de Murcia · 2025 · 1ª convocatoria · PY Tipo 1 · question 38 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.