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Situados en la posición l: 36º03'N L: 005º 50'W, damos rumbo al puerto de Tánger (luz de la farola del extremo del espigón del puerto) con una corrección total de 6º NE y una velocidad del buque de 10 nudos; teniendo en cuenta que nos afectará durante todo el recorrido una corriente de rumbo N80E e intensidad horaria = 2 nudos. Calcule el rumbo de aguja al puerto de Tánger, teniendo en cuenta los efectos de la corriente.In position l: 36º 03' N, L: 005º 50' W you set course for Tangier port breakwater light at 10 knots (Ct = 6º NE) in a current setting N80E at Ihc = 2 knots. Calculate the compass course to steer:

Show the answer

Correct answer: a) 179º

Why it is correct

From 36º 03′ N, 005º 50′ W to Tangier breakwater light (35º 47.4′ N, 005º 48.2′ W) the effective course is Ref = 175º. Solving the current triangle with Rc = 080º, Ihc = 2 knots and Vb = 10 knots gives Rv = 185º. With Ct = +6º (6º NE), the compass course is Ra = 185º − 6º = 179º.

Why the others are not

  • b) Does not offset the 10º drift from the N80E current or fails to subtract Ct = +6º.
  • c) Does not offset the 10º drift from the N80E current or fails to subtract Ct = +6º.
  • d) Does not offset the 10º drift from the N80E current or fails to subtract Ct = +6º.

How to work it out in the exam

  1. Plot Ref = 175º to Tangier and counteract the current (080º, 2 kn) with Vb = 10 kn ⇒ Rv = 185º.
  2. Subtract total compass error Ct = +6º: Ra = 185º − 6º = 179º.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.