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Al ser HRB: 14:00 nos encontramos al norte verdadero del Faro de Punta Malabata y a 5 millas de distancia y damos rumbo a pasar a 2 millas del faro de Punta Cires teniendo en cuenta que tenemos un viento del NORTE que nos produce un abatimiento de 15º. Declinación magnética = 4 ºNW y desvío de la aguja = +12º (más), velocidad del buque 5 nudos. Calcular el rumbo de aguja para pasar a 2 millas del Faro de Punta Cires.At HRB 14:00, 5 miles due North true of Punta Malabata lighthouse at 5 knots, you head to pass 2 miles off Punta Cires with a North wind causing 15º leeway (variation 4º NW, deviation +12º). Calculate the compass course Ra:
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Correct answer: a) 056º
Why it is correct
From 5 miles due North of Punta Malabata (35º 53.8′ N, 005º 45.0′ W), the tangent to pass 2 miles north of Punta Cires gives surface course Rs = 079º. With a North wind on the port side (+15º starboard leeway), steer 15º to port: Rv = 079º − 15º = 064º. With Ct = −4º + 12º = +8º, the compass course is Ra = 064º − 8º = 056º.
Why the others are not
- b) Adds instead of subtracting the 15º leeway or total compass error Ct = +8º.
- c) Adds instead of subtracting the 15º leeway or total compass error Ct = +8º.
- d) Adds instead of subtracting the 15º leeway or total compass error Ct = +8º.
How to work it out in the exam
- Plot 5′ N of Malabata and draw the tangent 2′ off Punta Cires: Rs = 079º.
- Subtract the 15º starboard leeway (Rv = 064º) and subtract Ct = +8º: Ra = 056º.
Where this question comes from
- Junta de Andalucía · 2018 · 1ª convocatoria · PY Módulo de navegación B · question 15 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.