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A Hrb: 12:00 En posición GPS l: 35º 57,4´N L: 005º 50,7´W damos rumbo al Puerto de Tánger (luz de la farola del extremo del espigón del puerto) Fl(3)12s14M, con velocidad de máquinas 6 nudos teniendo en cuenta que comienza a afectarnos la corriente general de la zona con rumbo de corriente Rc= 114º e intensidad horaria Ihc= 2 nudos y calculamos el rumbo de aguja (Ra) a Tánger (Corrección Total= - 8º).At Hrb 12:00 in GPS position l: 35º 57.4' N, L: 005º 50.7' W you head for Tangier port breakwater light at 6 knots engine speed in a current setting Rc = 114º at Ihc = 2 knots (Ct = –8º). Find Ra:
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Correct answer: b) Ra = 190º
Why it is correct
From 35º 57.4′ N, 005º 50.7′ W to Tangier breakwater (35º 47.4′ N, 005º 48.2′ W) the effective course is Ref = 169º. With current Rc = 114º, Ihc = 2 knots and Vm = 6 knots, the current triangle gives Rv = 182º. Applying Ct = −8º yields Ra = 182º − (−8º) = 190º.
Why the others are not
- a) Stops at true heading Rv = 182º or applies total compass error with the wrong sign.
- c) Stops at true heading Rv = 182º or applies total compass error with the wrong sign.
- d) Stops at true heading Rv = 182º or applies total compass error with the wrong sign.
How to work it out in the exam
- Plot Ref = 169º to Tangier and solve the triangle with Rc = 114º (2 kn) and Vm = 6 kn ⇒ Rv = 182º.
- Convert to compass course by subtracting Ct = −8º: Ra = 182º + 8º = 190º.
Where this question comes from
- Región de Murcia · 2025 · 3ª convocatoria · PY Tipo 1 · question 35 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.