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Al ser HRB = 11:00 nos encontramos al sudoeste (SW) verdadero del faro de Punta Paloma y a una distancia de 5 millas. Situados, damos rumbo a pasar a 5 millas del faro de Cabo Trafalgar, teniendo en cuenta que tenemos viento del noreste (NE) que nos produce un abatimiento de 15º. Declinación magnética = 3º NW y desvío de la aguja = +3º (más). Calcular el rumbo de aguja.At HRB 11:00 when 5 miles SW true of Punta Paloma lighthouse, you set course to pass 5 miles off Cape Trafalgar lighthouse with a NE wind causing 15º leeway (variation 3º NW, deviation +3º). Calculate the compass course Ra:
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Correct answer: c) 309º
Why it is correct
At 5 miles SW true (225º) of Punta Paloma (36º 04.0′ N, 005º 43.2′ W) we are at 36º 00.5′ N, 005º 47.6′ W. From there the tangent to pass 5 miles off Cape Trafalgar lighthouse is Rs = 294º. With a NE wind on the starboard side (15º port leeway), steer 15º to starboard: Rv = 294º + 15º = 309º. Since Ct = −3º + 3º = 0º, Ra = 309º.
Why the others are not
- a) Subtracts instead of adding 15º to offset the port leeway from the NE wind.
- b) Subtracts instead of adding 15º to offset the port leeway from the NE wind.
- d) Subtracts instead of adding 15º to offset the port leeway from the NE wind.
How to work it out in the exam
- Plot the start 5′ SW of Punta Paloma and draw the tangent 5′ off Cape Trafalgar: Rs = 294º.
- Add 15º to offset the NE wind and apply Ct = 0º: Ra = 309º.
Where this question comes from
- Junta de Andalucía · 2026 · 1ª convocatoria · PY Módulo de navegación · question 12 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.