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A HRB=0900, navegando al rumbo de aguja 041 (corrección total 06ºNW y velocidad 07 nudos) se toma demora de aguja a Cabo Espartel Da=076º. Seguimos navegando en las mismas condiciones y a HRB=1000, se toma una segunda demora de aguja a Cabo Espartel Da=196º y con estos datos se procede a situar en la carta la posición del yate a HRB=1000:At HRB 0900 steering Ra = 041º (Ct = 06º NW, speed 07 knots) you take Da Cape Spartel = 076º; maintaining course and speed, at HRB 1000 you take Da Cape Spartel = 196º. Plot your position at HRB 1000:
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Correct answer: a) 35º 51.1' N – 005º 54.4' W
Why it is correct
With Ct = −6º, true course is Rv = 041º − 6º = 035º, the first true bearing to Spartel is Dv₁ = 076º − 6º = 070º and the second is Dv₂ = 196º − 6º = 190º. In 1 hour (09:00 to 10:00) at 7 knots you run 7 miles along 035º; advancing Dv₁ by 7 miles along 035º to intersect Dv₂ gives 35º 51.1′ N, 005º 54.4′ W.
Why the others are not
- b) Does not advance the bearing Dv₁ = 070º by 7 miles along Rv = 035º to intersect Dv₂ = 190º.
- c) Does not advance the bearing Dv₁ = 070º by 7 miles along Rv = 035º to intersect Dv₂ = 190º.
- d) Does not advance the bearing Dv₁ = 070º by 7 miles along Rv = 035º to intersect Dv₂ = 190º.
How to work it out in the exam
- Compute Rv = 035º, Dv₁ = 070º and Dv₂ = 190º by subtracting 6º from the compass values.
- Advance the first bearing line 7 miles along 035º to intersect the second: 35º 51.1′ N, 005º 54.4′ W.
Where this question comes from
- Región de Murcia · 2026 · 1ª convocatoria · PY Tipo 1 · question 33 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.