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A Hrb=07:00, nos encontramos navegando al rumbo de aguja Ra=007º, momento en que se toma azimut de aguja de la estrella Polar (supuesta en el Polo) Za ⁜ = 355º. Calcular la corrección total (CT) en el momento de la observación.At 07:00 ship’s time, while steering compass course Ra = 007º, you observe a compass azimuth of Polaris (assumed at the Pole) Za = 355º. What is the total compass error (CT)?
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Correct answer: a) Total compass error (CT) = +005º
Why it is correct
With Polaris assumed at the North Pole (Zv = 360º), total compass error is CT = Zv − Za = 360º − 355º = +5º.
Why the others are not
- b) Does not subtract Za = 355º from true north (360º).
- c) Does not subtract Za = 355º from true north (360º).
- d) Does not subtract Za = 355º from true north (360º).
How to work it out in the exam
- Take the true azimuth of Polaris as Zv = 360º (000º).
- Compute CT = Zv − Za = 360º − 355º = +5º.
Where this question comes from
- Región de Murcia · 2025 · 3ª convocatoria · PY Tipo 1 · question 31 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.