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Nos encontramos navegando con Rumbo de aguja 120º, desvío 2º NW, declinación magnética 3º NW, y obtenemos simultáneamente marcación a Punta Paloma 108º por babor y marcación a Punta Alcázar 5º por estribor. ¿A qué distancia de Punta Malabata se encuentra la embarcación?Steering compass course 120º (deviation 2º NW, variation 3º NW), you take relative bearings 108º Port to Punta Paloma and 5º Starboard to Punta Alcázar. How far is the vessel from Punta Malabata?

Show the answer

Correct answer: b) 6.9 miles

Why it is correct

With Ct = −3º − 2º = −5º, true course is Rv = 120º − 5º = 115º. True bearings are Dv(Paloma) = 115º − 108º = 007º and Dv(Alcázar) = 115º + 5º = 120º, intersecting at 35º 55.6′ N, 005º 44.5′ W, 6.9 miles from Punta Malabata lighthouse.

Why the others are not

  • a) Does not match the 6.9-mile distance from the bearing intersection to Punta Malabata.
  • c) Does not match the 6.9-mile distance from the bearing intersection to Punta Malabata.
  • d) Does not match the 6.9-mile distance from the bearing intersection to Punta Malabata.

How to work it out in the exam

  1. Compute Rv = 115º, Dv(Paloma) = 007º and Dv(Alcázar) = 120º to fix the vessel on the chart.
  2. Measure the distance from that fix to Punta Malabata lighthouse: 6.9 miles.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.