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El día 10 de abril a hora legal Hz = 06h 13m 30s, un buque (A) se encuentra en longitud L = 132º 42’ W. En qué longitud se encontrará otro buque (B) si su hora civil del lugar es HcL = 09h 47m 06s del mismo día.On 10 April at zone time Hz = 06h 13m 30s, ship A is at longitude L = 132º 42’ W. At what longitude is ship B if her local civil time is HcL = 09h 47m 06s on the same day?
Show the answer
Correct answer: b) LB = 081º 36’ 00’’ W
Why it is correct
Ship A (132º 42′ W) is in zone +9 W, so HcG = 06h 13m 30s + 9h = 15h 13m 30s. The difference HcG − HcL(B) = 15h 13m 30s − 09h 47m 06s = 5h 26m 24s west, which at 15º/h equals 081º 36′ 00″ W.
Why the others are not
- a) Drops the 24 seconds of time difference (24s × 15″/s = 6′).
- c) Uses ship A's local civil time instead of her +9 W zone time.
- d) Subtracts the minutes and seconds between HcG and HcL(B) incorrectly.
How to work it out in the exam
- 5h = 75º, 26m = 6º 30′ and 24s = 6′ → 081º 36′ W.
Where this question comes from
- Región de Murcia · 2024 · 3ª convocatoria · CY Tipo 1 · question 17 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.