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En aguas de Portugal a 100 millas al Oeste del puerto de Figueira da Foz, en la madrugada del día 29 de Marzo de 2020, a hora civil de Greenwich 0430, en situación estimada= 40º 10,6’N 011º 03,2’W, obtenemos de la estrella Arcturus (nº=69) los siguientes datos: Declinación= +19º 04,6' y ángulo en el Polo (P)= 21º 30,4’W Procedemos a calcular el azimut verdadero a dicha estrella en su valor circular, utilizando las fórmulas que resuelven los ángulos del triángulo de posición:In Portuguese waters 100 miles west of Figueira da Foz, in the early hours of 29 March 2020, at Greenwich civil time 0430, at DR position 40º 10.6’N 011º 03.2’W, we obtain for the star Arcturus: Declination = +19º 04.6' and angle at the pole (P) = 21º 30.4’W. We calculate the star’s true azimuth in circular notation.
Show the answer
Correct answer: c) 227.5º
Why it is correct
The star is to the west: Z = 360º − 132.5º = 227.5º.
Why the others are not
- a) It does not match the working.
- b) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- tan Z = sin P / (cos l tan d − sin l cos P).
- Body to the E: Z from north. To the W: 360º − Z.
Where this question comes from
- Región de Murcia · 2020 · 1ª convocatoria · CY Tipo 1 · question 16 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.