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A hora civil de Greenwich 1350, continúan navegando sin novedad hacia Ciudad del Cabo y en ese instante su situación estimada es 23º 27,2’S - 041º 27,2’W y con declinación del Sol = + 00º 39,3’ y ángulo en el Polo = 15º 41,5’ E. Calcula el azimut verdadero del Sol, en su valor circular utilizando las fórmulas que resuelven los lados y ángulos del triángulo de posición.At Greenwich civil time 1350, still sailing towards Cape Town, the DR position is 23º 27.2′S 041º 27.2′W, with the Sun’s declination + 00º 39.3′ and meridian angle 15º 41.5′ E. Calculate the Sun’s true azimuth, in circular notation, using the position triangle formulas.
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Correct answer: a) 034.48º
Why it is correct
The formula gives N 34.5º E. In the morning, from 23ºS, the Sun is north of us: 034.5º.
Why the others are not
- b) That is the supplement. The Sun is north, not south.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- tan Z = sin P / (cos l tan d − sin l cos P), with south negative.
- P east: Z from north towards east.
Where this question comes from
- Región de Murcia · 2019 · 1ª convocatoria · CY Tipo 1 · question 17 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.