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29 Junio 2021: A HcG= 130058, se encuentran en situación estimada= 40º 07,2'N - 014º 25,0'W. En ese instante y esa situación, se produce el paso del Sol por el meridiano móvil del yate y obtienen altura verdadera del Sol= 72º 59,5' y declinación del Sol= +23º 11,7’ y tras calcular el valor de la distancia zenital con su signo correspondiente, rectifican la latitud por meridiana del Sol:29 June 2021: at Greenwich civil time 130058, they are at DR position 40º 07.2'N - 014º 25.0'W. At that moment the Sun passes the yacht’s moving meridian, and they get a true Sun altitude of 72º 59.5' and declination +23º 11.7’. Having worked out the zenith distance, they find the observed latitude:
Show the answer
Correct answer: a) 40º 12.2'N
Why it is correct
z = 17º 00.5′. l = 23º 11.7′ + 17º 00.5′ = 40º 12.2′ N.
Why the others are not
- b) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- z = 90º − a.
- Facing south: l = d + z.
Where this question comes from
- Región de Murcia · 2021 · 2ª convocatoria · CY Tipo 1 · question 18 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.