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Con una situación de salida l= 36º 00’ N; L= 006º 10’ W, rumbo directo 278º y distancia navegada 40 millas. Determinar la situación de llegada.With departure at l= 36º 00’ N; L= 006º 10’ W, direct course 278º and distance run 40 miles. Find the arrival position.
Show the answer
Correct answer: a) l=36º 5.6’N; L= 006º 59’ W.
Why it is correct
Δlat = 40 × cos 278º = 5.6′ N. Departure = 39.6′ W. ΔLong = 49′. Arrival: 36º 05.6′ N, 006º 59′ W.
Why the others are not
- b) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- Find the difference of latitude and the departure: ΔL × cos(mean latitude).
- Course = arctan(A / Δlat). Distance = root of the sum of squares.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2025 · Convocatoria de abril · PY Test 1 · question 33 Official paper · Official answer key
- Ministerio de Transportes (Madrid) · 2025 · Convocatoria de abril · PY Test 2 · question 37 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.