Hover or tap underlined Spanish terms to see their translation and exam tip.
Navegando al rumbo verdadero 258° a 10 nudos al ser 02h30 min se toma demora verdadera de Punta Carnero 321°. A 03h00 min demora verdadera de Punta Carnero 020°. Calcular situación a 03h00 min.Steaming on true course 258° at 10 knots, you take true bearing Dv Punta Carnero = 321° at 02h 30m and Dv Punta Carnero = 020° at 03h 00m. Calculate your position at 03h 00m:
Show the answer
Correct answer: c) 35° 59.5' N 005° 27.9' W.
Why it is correct
In the 30 minutes from 02h 30m to 03h 00m at 10 knots the vessel runs 5 miles along Rv = 258º. Advancing the first bearing line Dv₁ = 321º (reciprocal 141º from Punta Carnero) by 5 miles along 258º to intersect the second bearing Dv₂ = 020º (reciprocal 200º from Carnero) gives 35º 59.5′ N, 005º 27.9′ W.
Why the others are not
- a) Does not advance the first Punta Carnero bearing 5 miles along Rv = 258º to intersect Dv₂ = 020º.
- b) Does not advance the first Punta Carnero bearing 5 miles along Rv = 258º to intersect Dv₂ = 020º.
- d) Does not advance the first Punta Carnero bearing 5 miles along Rv = 258º to intersect Dv₂ = 020º.
How to work it out in the exam
- Plot the reciprocal bearings 141º and 200º from Punta Carnero lighthouse.
- Advance the first bearing 5 miles (30 min at 10 knots) along 258º to intersect the second: 35º 59.5′ N, 005º 27.9′ W.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2020 · Convocatoria de diciembre · PY Test 1 · question 36 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.