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El día 05 de noviembre de 2022, en situación 36º 10,0′ N y 005 10,0′ W damos rumbo para pasar a 4 millas del faro de punta Carnero, teniendo en cuenta que sopla viento del NW que nos produce un abatimiento de 12º. Declinación magnética = 1º NW y Desvío de la aguja = –4º (menos). Calcular el rumbo de aguja.On 5 November 2022 in position 36º 10.0' N, 005º 10.0' W you set course to pass 4 miles off Punta Carnero lighthouse with a NW wind causing 12º leeway (variation 1º NW, deviation –4º). Calculate the compass course Ra:
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Correct answer: d) 247º
Why it is correct
From 36º 10.0′ N, 005º 10.0′ W the tangent to pass 4 miles off Punta Carnero lighthouse gives surface course Rs = 230º. With a NW wind on the starboard side (12º port leeway), steer 12º to starboard: Rv = 230º + 12º = 242º. With Ct = −1º − 4º = −5º, the compass course is Ra = 242º − (−5º) = 247º.
Why the others are not
- a) Subtracts instead of adding 12º to offset the NW wind or misapplies Ct = −5º.
- b) Subtracts instead of adding 12º to offset the NW wind or misapplies Ct = −5º.
- c) Subtracts instead of adding 12º to offset the NW wind or misapplies Ct = −5º.
How to work it out in the exam
- Draw from 36º 10.0′ N, 005º 10.0′ W the tangent 4 miles off Punta Carnero: Rs = 230º.
- Offset the NW leeway (Rv = 230º + 12º = 242º) and apply Ct = −5º: Ra = 247º.
Where this question comes from
- Junta de Andalucía · 2022 · 3ª convocatoria · PY Módulo de navegación · question 12 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.