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Navegando a Ra= 151º con velocidad de máquina de 8 nudos, a Hrb= 10:30 del día 15 de noviembre de 2025 tomamos una demora de aguja al Faro de Cabo Roche de 034º, a Hrb= 10:50 del mismo día tomamos distancia radar al Faro de Cabo Trafalgar de 7 millas. El desvío es de 1,5º(E) y la declinación magnética será la del año en curso. Obtener nuestra situación verdadera a Hrb= 10:50. Elija la respuesta más aproximada.On 15 November 2025 steering Ra = 151º at 8 knots (deviation 1.5º E), Da Cabo Roche = 034º at 10:30 and radar distance to Cape Trafalgar = 7 miles at 10:50. Find your true position at 10:50:

Show the answer

Correct answer: a) l = 036º 10.8' N; L = 006º 10.7' W.

Why it is correct

In 2025 charted variation is dm ≈ −0.5º; with deviation +1.5º, Ct = +1º, Rv = 152º and Dv(Roche) = 035º. In 20 minutes (10:30 to 10:50) at 8 knots you run 2.7 miles along 152º; advancing the Cabo Roche bearing line 2.7′ along 152º to intersect the 7-mile arc from Trafalgar gives l = 36º 10.8′ N, L = 006º 10.7′ W.

Why the others are not

  • b) Does not advance the Cabo Roche bearing 2.7 miles along 152º to intersect the 7′ arc from Trafalgar.
  • c) Does not advance the Cabo Roche bearing 2.7 miles along 152º to intersect the 7′ arc from Trafalgar.
  • d) Does not advance the Cabo Roche bearing 2.7 miles along 152º to intersect the 7′ arc from Trafalgar.

How to work it out in the exam

  1. Compute Ct = +1º, Rv = 152º, Dv(Roche) = 035º and distance run d = 2.7′ in 20 min.
  2. Advance the Roche bearing 2.7′ along 152º and intersect with the 7′ arc from Trafalgar: 36º 10.8′ N, 006º 10.7′ W.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.