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Navegando al rumbo de aguja 185° y a una velocidad de máquinas de 6 nudos, a Hrb: 07:45 del día 15 de agosto de 2024, tomamos una demora de aguja al Faro de Punta Carnero de 310°, a Hrb: 08:15 del mismo día tomamos una demora de aguja de 195° al Faro de Punta Almina. El desvío es 2°(W) y la declinación magnética será la del año en curso. Determinar nuestra situación a Hrb: 08:15.On 15 August 2024 steering Ra = 185° at 6 knots (deviation 2° W), you take Da Punta Carnero = 310° at 07:45 and Da Punta Almina = 195° at 08:15. Determine your position at 08:15:

Show the answer

Correct answer: c) l = 35° 55.6' N; L = 005° 16.4' W.

Why it is correct

In 2024 charted variation is dm ≈ −0.6º; with deviation −2º, Ct = −2.6º, Rv = 182.4º, Dv(Carnero) = 307.4º and Dv(Almina) = 192.4º. Advancing the first bearing line 3 miles (30 min at 6 knots) along Rv = 182.4º to intersect the second bearing to Punta Almina gives l = 35º 55.6′ N, L = 005º 16.4′ W.

Why the others are not

  • a) Does not advance the first bearing 3 miles South or has the wrong longitude degree (006º).
  • b) Does not advance the first bearing 3 miles South or has the wrong longitude degree (006º).
  • d) Does not advance the first bearing 3 miles South or has the wrong longitude degree (006º).

How to work it out in the exam

  1. Compute Ct = −2.6º, Rv = 182.4º, Dv(Carnero) = 307.4º and Dv(Almina) = 192.4º.
  2. Advance the Carnero bearing 3 miles (30 min at 6 knots) along 182.4º and intersect with Almina: 35º 55.6′ N, 005º 16.4′ W.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.