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Con los mismos datos anteriores (HRB= 1320, Situación= 35º 57,4´N 005º 50,7´W, velocidad de corredera= 6 nudos y la corriente de Rc= 114º y Ihc= 2 nudos); hallan el valor de la velocidad efectiva hacia Tánger y calculan la HRB de llegada a dicho PuertoFrom 35º 57.4' N, 005º 50.7' W at HRB 1320 heading for Tangier breakwater light at 6 knots log speed in a current setting Rc = 114º at Ihc = 2 knots, find your HRB of arrival at Tangier:
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Correct answer: b) 1448
Why it is correct
The distance from 35º 57.4′ N, 005º 50.7′ W to Tangier breakwater (35º 47.4′ N, 005º 48.2′ W) is 10.2 miles along Ref = 169º. From the current triangle (Rc = 114º, Ihc = 2 knots, Vb = 6 knots) effective speed is Vef = 6.95 knots; time is 10.2 / 6.95 = 1.47 h (1h 28m) ⇒ HRB = 13:20 + 1h 28m = 1448.
Why the others are not
- a) Does not divide the 10.2 miles by the effective speed Vef = 6.95 knots from the current triangle.
- c) Does not divide the 10.2 miles by the effective speed Vef = 6.95 knots from the current triangle.
- d) Does not divide the 10.2 miles by the effective speed Vef = 6.95 knots from the current triangle.
How to work it out in the exam
- Measure the distance to Tangier (10.2 miles) and find Vef = 6.95 knots from the current triangle.
- Compute time t = 10.2 / 6.95 = 1h 28m and add to 13:20: HRB = 1448.
Where this question comes from
- Región de Murcia · 2021 · 3ª convocatoria · PY Tipo 1 · question 37 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.