Hover or tap underlined Spanish terms to see their translation and exam tip.
A HRB = 1115 tomamos situación GPS de un punto -A- 36º 08'N – 005º 11'W y damos rumbo sin viento ni corriente hacia un punto -B- 36º 29'N – 004º 57W. Calculamos el rumbo loxodrómico en su valor circular entre ambos puntosAt ship’s clock 1115 we take a GPS position at point A 36º 08'N – 005º 11'W and set course, with no wind or current, for point B 36º 29'N – 004º 57W. We calculate the rhumb line course in circular notation between them
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Correct answer: a) 028º
Why it is correct
Δlat = 21′ N. Departure = 14′ × cos 36º18′ = 11.3′ E. Course = arctan(11.3 / 21) = 28º.
Why the others are not
- b) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- Find the difference of latitude and the departure: ΔL × cos(mean latitude).
- Course = arctan(A / Δlat). Distance = root of the sum of squares.
Where this question comes from
- Región de Murcia · 2019 · 1ª convocatoria · PY Tipo 1 · question 39 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.