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A Hrb: 08:20 estando en situación l= 39º 22’ N; L= 003º 28’W se quiere llegar a Hrb: 11:50 al punto l= 40º 07’N; L= 003º 7’ W. Si la corrección total es Ct= 9,3º(-), indique qué rumbo hay que dar al timonel y la velocidad de máquinas que hay que meter.At ship’s clock 08:20 at l= 39º 22’ N; L= 003º 28’W we want to reach l= 40º 07’N; L= 003º 7’ W at 11:50. If the total correction is -9.3º, what course should we give the helmsman and what engine speed?
Show the answer
Correct answer: a) Compass 29º / 13.7 knots.
Why it is correct
True 019.7º, 47.8 miles. Compass = 19.7º + 9.3º = 29º. Speed: 47.8 / 3.5 h = 13.7 knots.
Why the others are not
- b) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- Find the difference of latitude and the departure: ΔL × cos(mean latitude).
- Course = arctan(A / Δlat). Distance = root of the sum of squares.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2024 · Convocatoria de noviembre · PY Test 1 · question 36 Official paper · Official answer key
- Ministerio de Transportes (Madrid) · 2024 · Convocatoria de noviembre · PY Test 2 · question 40 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.