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Al ser HRB = 06:00 nos encontramos en situación 35º 50,0′ N, 005º 50,0′ W, navegando al rumbo de aguja = 350º. Sopla viento del oeste (W) que nos produce un abatimiento de 20º. Calcular el rumbo que realiza el barco afectado por el viento, sabiendo que la declinación magnética = 5º NE y el desvío de la aguja = +10º (más).At ship’s clock 06:00 we are at 35º 50.0′ N, 005º 50.0′ W, on compass course 350º. A westerly wind gives 20º of leeway. Calculate the course made by the boat under the wind, given magnetic variation = 5º NE and compass deviation = +10º (plus).
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Correct answer: a) 025º
Why it is correct
Total correction +15º, true 005º. The west wind comes from port and pushes to starboard: 005º + 20º = 025º.
Why the others are not
- b) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- True = compass + total correction.
- Wind to port: add leeway. To starboard: subtract it.
Where this question comes from
- Junta de Andalucía · 2025 · 1ª convocatoria · PY Módulo de navegación · question 16 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.