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En situación l= 10º 20’N y L= 100º 33’W, navegando a RA = 100º y Vm = 10 nudos. Se pide calcular la situación dentro de 1h y 48 min siendo la CT = +3º (Resolver el problema analíticamente):At l= 10º 20’N and L= 100º 33’W, sailing on compass course 100º at 10 knots. Calculate the position 1h 48 min later, the total correction being +3º (solve analytically):
Show the answer
Correct answer: d) l= 10º 16’ N ; L= 100º 15.2’ W
Why it is correct
True 103º and d = 18 miles. Δlat = 4.0′ S. Departure = 17.5′ E. ΔLong = 17.8′. Arrival: 10º 16′ N, 100º 15.2′ W.
Why the others are not
- a) It does not match the working.
- b) It does not match the working.
- c) It does not match the working.
How to work it out in the exam
- Find the true course and distance.
- Δlat = d × cos R. Departure = d × sin R. ΔLong = departure / cos(mean latitude).
Where this question comes from
- Región de Murcia · 2024 · 1ª convocatoria · PY Tipo 1 · question 39 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.