Hover or tap underlined Spanish terms to see their translation and exam tip.
Al ser Hrb=18-24, un yate se encuentra en l=36º 11'0N y L=005º 13'0W y pone rumbo a la luz verde del puerto de Ceuta a una velocidad de 5 nudos teniendo en cuenta un viento de poniente que le produce 5º de abatimiento. Ct= 8º NW. ¿Cuál será el Ra y la hora de llegada?At Hrb 18-24 a yacht in l = 36º 11.0' N and L = 005º 13.0' W sets course for Ceuta port green light at 5 knots with a West wind causing 5º leeway and Ct = 8º NW. Find Ra and arrival time:
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Correct answer: a) 208º and 21-57
Why it is correct
From 36º 11.0′ N, 005º 13.0′ W to Ceuta green light (35º 53.8′ N, 005º 18.6′ W) the surface course is Rs = 195º and distance is 17.8 miles. With a West wind on the starboard side (5º port leeway), Rv = 195º + 5º = 200º; with Ct = −8º (8º NW), Ra = 200º + 8º = 208º. At 5 knots, 17.8 miles take 3h 33m ⇒ arrival at 18:24 + 3h 33m = 21-57.
Why the others are not
- b) Does not offset the westerly wind to starboard (+5º) or fails to add the 8º negative compass error.
- c) Does not offset the westerly wind to starboard (+5º) or fails to add the 8º negative compass error.
- d) Does not offset the westerly wind to starboard (+5º) or fails to add the 8º negative compass error.
How to work it out in the exam
- Measure on the chart the course (Rs = 195º) and distance (17.8 miles) to Ceuta green light.
- Add 5º leeway and 8º Ct (Ra = 208º) and add 3h 33m (17.8′ at 5 kn) to 18-24: 21-57.
Where this question comes from
- Junta de Andalucía · 2021 · 1ª convocatoria · PY Módulo de navegación · question 13 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.