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A HRB= 1345, ya están fuera del dispositivo de separación de tráfico y en ese instante toman simultáneamente demoras de aguja a los faros de: • Punta Paloma= 061º • Punta de Gracia= 018º • Trafalgar= 325º Corrección total= 6º NW y se sitúan en la carta:At HRB 1345 outside the TSS, you simultaneously take compass bearings Da Punta Paloma = 061º, Da Punta de Gracia = 018º and Da Trafalgar = 325º with Ct = 6º NW. Plot your position:

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Correct answer: b) 36º 00' N – 005º 50' W

Why it is correct

Subtracting the 6º negative compass error gives true bearings: Dv(Paloma) = 055º, Dv(Punta de Gracia) = 012º and Dv(Trafalgar) = 319º. Plotting the three position lines from their respective lighthouses intersects at 36º 00′ N, 005º 50′ W.

Why the others are not

  • a) Does not match the intersection point of Dv(Paloma) = 055º, Dv(Gracia) = 012º and Dv(Trafalgar) = 319º.
  • c) Does not match the intersection point of Dv(Paloma) = 055º, Dv(Gracia) = 012º and Dv(Trafalgar) = 319º.
  • d) Does not match the intersection point of Dv(Paloma) = 055º, Dv(Gracia) = 012º and Dv(Trafalgar) = 319º.

How to work it out in the exam

  1. Convert all three bearings to true by subtracting 6º: 055º, 012º and 319º.
  2. Plot their reciprocals (235º, 192º and 139º) on the chart: they intersect at 36º 00′ N, 005º 50′ W.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.