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HRB= 0300, navegan al rumbo de aguja= 132º y velocidad del buque= 12 nudos, sin viento ni corriente que les afecten y en ese instante toman azimut de aguja de la Estrella Polar (supuesta en el Polo)= 007º Calculan el rumbo verdadero (Rv) que llevan:At HRB 0300 steering compass course Ra = 132º at 12 knots without wind or current, you take a compass azimuth of Polaris (assumed at the Pole) = 007º. Calculate your true course (Rv):
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Correct answer: b) 125º
Why it is correct
Assuming Polaris at true north (Zv = 000º), total compass error is Ct = Zv − Za = 000º − 007º = −7º. Therefore true course is Rv = Ra + Ct = 132º − 7º = 125º.
Why the others are not
- a) Adds instead of subtracting the 7º negative compass error from the compass course.
- c) Adds instead of subtracting the 7º negative compass error from the compass course.
- d) Adds instead of subtracting the 7º negative compass error from the compass course.
How to work it out in the exam
- Compute total compass error from Polaris: Ct = 000º − 007º = −7º.
- Add Ct algebraically to the compass course: Rv = 132º − 7º = 125º.
Where this question comes from
- Región de Murcia · 2020 · 1ª convocatoria · PY Tipo 1 · question 31 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.