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A las 15:00 HRB, navegando con Rumbo de aguja = 245º a una Velocidad de máquinas = 5 nudos, tomamos simultáneamente Demora de aguja al Faro de Punta Carnero = 023º y distancia al mismo = 4,1´. Con viento del Norte que nos abate 4º y con corriente de Rumbo = 230º e intensidad = 2 nudos. Calcule situación a las 17:00 sabiendo que la Corrección total es 0º.At 15:00 steering Ra = 245º at 5 knots (Ct = 0º), Punta Carnero bears Da = 023º at 4.1 miles. With a North wind giving 4º leeway and a current setting 230º at 2 knots, calculate your position at 17:00:
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Correct answer: a) 35º 53.40' N 005º 41.9' W
Why it is correct
At 15:00 we are 4.1′ on 203º from Punta Carnero (36º 00.5′ N, 005º 27.4′ W). With Ct = 0º, Rv = 245º; the North wind sets us 4º to port ⇒ Rs = 245º − 4º = 241º. Over 2 hours (15:00 to 17:00) we run 10 miles along 241º plus 4 miles of current along 230º, reaching 35º 53.40′ N, 005º 41.9′ W.
Why the others are not
- b) Does not combine the 10 miles on Rs = 241º with the 4 miles of current on 230º from the start.
- c) Does not combine the 10 miles on Rs = 241º with the 4 miles of current on 230º from the start.
- d) Does not combine the 10 miles on Rs = 241º with the 4 miles of current on 230º from the start.
How to work it out in the exam
- Plot the start 4.1′ on 203º from Punta Carnero and compute Rs = 245º − 4º = 241º.
- Plot 10 miles on 241º (2 h at 5 knots) and add 4 miles on 230º (2 h at 2 knots): 35º 53.40′ N, 005º 41.9′ W.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2019 · Convocatoria de junio · PY Test 1 · question 32 Official paper · Official answer key
- Ministerio de Transportes (Madrid) · 2019 · Convocatoria de junio · PY Test 2 · question 32 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.