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Un buque se encuentra en situación 13º N, 176º 30,0´E y desea navegar hasta el punto 11º S, 174º 50,0´E. Calcular el rumbo directo (Aproximar al medio grado) y distancia a navegar.A ship at 13º N, 176º 30.0´E wants to sail to 11º S, 174º 50.0´E. Calculate the direct course (to the nearest half degree) and distance.

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Correct answer: c) 184º 1443 miles

Why it is correct

Δlat = 1440′ S, crossing the Equator. Departure = 100′ W. Course S 4º W, or 184º, and 1443 miles.

Why the others are not

  • a) It does not match the working.
  • b) It does not match the working.
  • d) It does not match the working.

How to work it out in the exam

  1. Find the difference of latitude and the departure: ΔL × cos(mean latitude).
  2. Course = arctan(A / Δlat). Distance = root of the sum of squares.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.