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A Hora del Reloj de Bitácora (HRB)= 08:30 navegamos al Ra = 096º, Ct= 6° NW, y en ese instante tenemos por la proa al faro de Punta de Gracia y por nuestro través de babor, al faro de Trafalgar. ¿En qué posición nos encontramos?With Punta de Gracia dead ahead and Trafalgar abeam to port at 08:30 while steering Ra = 096º (Ct = 6° NW), what is your charted position?

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Correct answer: a) 36º 05.4' N - 006º 02.0' W

Why it is correct

With Ra = 096º and Ct = −6º, true course is Rv = 090º (due East). Having Punta de Gracia dead ahead (Dv = 090º) fixes latitude at l = 36º 05.4′ N, and having Trafalgar abeam to port (Dv = 000º) fixes longitude at L = 006º 02.0′ W.

Why the others are not

  • b) Does not match the intersection of the Punta de Gracia parallel (36º 05.4′ N) with the Trafalgar meridian (006º 02.0′ W).
  • c) Does not match the intersection of the Punta de Gracia parallel (36º 05.4′ N) with the Trafalgar meridian (006º 02.0′ W).
  • d) Does not match the intersection of the Punta de Gracia parallel (36º 05.4′ N) with the Trafalgar meridian (006º 02.0′ W).

How to work it out in the exam

  1. Compute Rv = 096º − 6º = 090º ⇒ parallel of Punta de Gracia (36º 05.4′ N).
  2. With Trafalgar abeam to port (Dv = 000º), read its meridian: 006º 02.0′ W.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.