Hover or tap underlined Spanish terms to see their translation and exam tip.
Desde la posición 35º 50'N – 006º 00'W damos rumbo hacia la posición 36º 00'N - 005º 50º W. Calcule el rumbo de aguja que hay que poner, sabiendo que la corrección total para ese rumbo es de 4º NE:Steering from 35º 50' N, 006º 00' W towards 36º 00' N, 005º 50' W with total compass error Ct = 4º NE, calculate the compass course to steer:
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Correct answer: b) Ra = 036º
Why it is correct
Joining 35º 50′ N, 006º 00′ W to 36º 00′ N, 005º 50′ W on the chart (Δl = 10′ N, ΔL = 10′ E ⇒ A = 8.1′ E) gives true course Rv = 040º. With Ct = +4º (NE), the compass course is Ra = Rv − Ct = 040º − 4º = 036º.
Why the others are not
- a) Does not subtract Ct = +4º from the true course Rv = 040º between the two positions.
- c) Does not subtract Ct = +4º from the true course Rv = 040º between the two positions.
- d) Does not subtract Ct = +4º from the true course Rv = 040º between the two positions.
How to work it out in the exam
- Plot on the chart the true course from 35º 50′ N, 006º 00′ W to 36º 00′ N, 005º 50′ W: Rv = 040º.
- Subtract the positive compass error: Ra = 040º − 4º = 036º.
Where this question comes from
- Región de Murcia · 2018 · 2ª convocatoria · PER Tipo 1 · question 44 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.