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Dada la situación de salida l= 35º45'N; L= 005º14' W, la Hrb= 15:00 h, la velocidad de la embarcación 5 nudos y el rumbo de aguja 355º. Ct=+5º. Se pide calcular la situación de estima a Hrb= 16:30 h.Given a departure position l= 35º45'N; L= 005º14' W, ship’s clock 15:00, boat speed 5 knots and compass course 355º. Total correction = +5º. Calculate the dead reckoning position at 16:30.
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Correct answer: d) l= 35º52.5'N; L= 005º14' W.
Why it is correct
True course = 355º + 5º = 000º: longitude does not change. 1.5 h at 5 knots is 7.5 miles, which is 7.5′ of latitude.
Why the others are not
- a) The working gives 35º 52,5′ N, 005º 14′ W, and this option does not match.
- b) The working gives 35º 52,5′ N, 005º 14′ W, and this option does not match.
- c) The working gives 35º 52,5′ N, 005º 14′ W, and this option does not match.
How to work it out in the exam
- Find the true course: true = compass + total correction.
- Distance = speed × time.
- Draw the course on the chart, measure the distance and read the position.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2024 · Convocatoria de abril · PER Test 1 · question 45 Official paper · Official answer key
- Ministerio de Transportes (Madrid) · 2024 · Convocatoria de abril · PER Test 3 · question 43 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.