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Situados en posición l=35º 50´ N y L= 006º 10´W Navegamos a Rv= 032º y a una Velocidad= 6 Nudos, transcurridas 2,5 horas, ¿A qué distancia de Punta Gracia nos encontraremos?From position l = 35º 50' N and L = 006º 10' W you sail on true course Rv = 032º at a speed of 6 knots. How far from Punta de Gracia will you be after 2.5 hours?
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Correct answer: b) 10 miles
Why it is correct
In 2.5 hours at 6 knots you run 15 miles. Plotting 15 miles along Rv = 032º from 35º 50′ N, 006º 10′ W reaches 36º 02.7′ N, 006º 00.2′ W, which lies 10 miles from Punta de Gracia lighthouse (36º 05.4′ N, 005º 48.6′ W).
Why the others are not
- a) Does not match the 10-mile distance from the point reached after 15 miles on 032º to Punta de Gracia.
- c) Does not match the 10-mile distance from the point reached after 15 miles on 032º to Punta de Gracia.
- d) Does not match the 10-mile distance from the point reached after 15 miles on 032º to Punta de Gracia.
How to work it out in the exam
- Plot 15 miles (2.5 h at 6 knots) along Rv = 032º from 35º 50′ N, 006º 10′ W.
- Measure the distance from the final point to Punta de Gracia lighthouse: 10 miles.
Where this question comes from
- Junta de Andalucía · 2021 · 2ª convocatoria · PER Modelo B · question 45 Official paper · Official answer key
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Pending instructor review. Machine translation, not reviewed.