Hover or tap underlined Spanish terms to see their translation and exam tip.
Situados en las coordenadas = 35º 45'N – 006º 15'W, damos rumbo hacia un punto – P – cuyas coordenadas son = 36º 00'N – 006º 00'W con velocidad del yate = 10 nudos y corrección total para el rumbo resultante = 8º NW. Calcular el rumbo de aguja al punto – P – :At 35º 45'N – 006º 15'W, we set course for a point P at 36º 00'N – 006º 00'W at a speed of 10 knots with a total correction for the resulting course of 8º NW. Calculate the compass course to point P:
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Correct answer: c) 047º
Why it is correct
Difference of latitude: 15′. Departure: 15′ × cos 35º52′ = 12.2. True course = arctan(12.2 / 15) = 39º. Compass course = true − total correction = 39º − (−8º) = 47º.
Why the others are not
- a) It is several degrees out.
- b) It applies only half the correction.
- d) It is several degrees out.
How to work it out in the exam
- Measure the true course.
- Compass = true − total correction, with NW negative.
Where this question comes from
- Región de Murcia · 2018 · 3ª convocatoria · PER Tipo 1 · question 42 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.