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A Hrb 12:00, navegando con rumbo de aguja= 275º y un desvío de 2º (+), situados en la oposición de los Faros Punta Paloma y Punta Malabata, se toma demora de aguja a Punta de Gracia=337º. Una vez situados, se da rumbo al Faro de Cabo Trafalgar con un desvío de aguja de 4º (+) y una velocidad de máquina de 8 nudos. Calcular el rumbo de aguja al Faro de Cabo Trafalgar y la Hrb cuando nos encontremos al través del Faro de Barbate. Supóngase que en el momento de la navegación la declinación magnética en toda la zona es de 5ºW.At 12:00 on Ra = 275º (deviation +2º, variation 5º W) on the Punta Paloma–Punta Malabata opposition with Da Punta de Gracia = 337º, you head for Cape Trafalgar (new deviation +4º) at 8 knots. Find Ra and the time when abeam of Barbate light:

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Correct answer: b) Ra = 313º; Hrb = 14:00.

Why it is correct

At 12:00, Ct = −5º + 2º = −3º and Dv(Gracia) = 334º, intersecting the Paloma–Malabata opposition at 35º 57.5′ N, 005º 44.2′ W. From there to Cape Trafalgar, true course is Rv = 312º; with new deviation +4º (Ct = −5º + 4º = −1º), Ra = 312º − (−1º) = 313º. To abeam of Barbate (perpendicular bearing 042º) is 16.0 miles (2 h at 8 knots ⇒ 14:00).

Why the others are not

  • a) Does not match Ra = 313º (Rv = 312º, Ct = −1º) and the 2-hour run to abeam of Barbate.
  • c) Does not match Ra = 313º (Rv = 312º, Ct = −1º) and the 2-hour run to abeam of Barbate.
  • d) Does not match Ra = 313º (Rv = 312º, Ct = −1º) and the 2-hour run to abeam of Barbate.

How to work it out in the exam

  1. Fix the start on the Paloma–Malabata opposition with Dv(Gracia) = 334º and lay course to Trafalgar (Rv = 312º ⇒ Ra = 313º).
  2. Drop the perpendicular to the track from Barbate and measure 16 miles (2 h at 8 knots ⇒ 14:00).

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.