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A Hrb=12:00, navegando con rumbo de aguja= 095° y un desvío= 3° (-), situados en la oposición de los Faros Punta Paloma y de Punta Malabata, se toma marcación a Punta Alcazar= 30° Estribor. Una vez situados, se pide calcular el rumbo de aguja para pasar a 4 millas al Norte verdadero del Faro de Cabo Espartel, el desvío para el nuevo rumbo es 3,5° (-). La declinación magnética para toda la zona de navegación es de 2°(W).At 12:00 on Ra = 095º (deviation –3º, variation 2º W) on the Punta Paloma–Punta Malabata opposition, you take a 30º Starboard relative bearing to Punta Alcázar, then head for 4 miles North true of Cape Spartel (new deviation –3.5º). Find Ra:

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Correct answer: b) Ra = 250º.

Why it is correct

With Ct = −2º − 3º = −5º, Rv = 095º − 5º = 090º and Dv(Alcázar) = 090º + 30º = 120º, intersecting the Paloma–Malabata opposition at 35º 54.5′ N, 005º 44.3′ W. From there to 4 miles N of Cape Spartel (35º 51.5′ N, 005º 55.5′ W), true course is Rv = 244.5º; with new Ct = −2º − 3.5º = −5.5º, Ra = 244.5º + 5.5º = 250º.

Why the others are not

  • a) Does not match Rv = 244.5º minus the new Ct = −5.5º (Ra = 250º).
  • c) Does not match Rv = 244.5º minus the new Ct = −5.5º (Ra = 250º).
  • d) Does not match Rv = 244.5º minus the new Ct = −5.5º (Ra = 250º).

How to work it out in the exam

  1. Compute Rv = 090º and Dv(Alcázar) = 120º to fix your position on the Paloma–Malabata opposition.
  2. Measure the course to 4′ N of Spartel (Rv = 244.5º) and subtract the new Ct = −5.5º: Ra = 250º.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.