Hover or tap underlined Spanish terms to see their translation and exam tip.
A HRB (Hora reloj bitácora) 10:00 estamos en la posición A, cuyas coordenadas son: Latitud: 35°45’N / Longitud: 006°15’W. Desde esta posición damos rumbo para dirigirnos a la posición B, de coordenadas: Latitud: 36°00’N / Longitud: 006°00’W. Con una variación local de 2°NW y un desvío de aguja de (-6º). Calcular el rumbo de aguja.At 10:00 by the ship’s clock we are at position A: Latitude 35°45’N / Longitude 006°15’W. From here we set course for position B: Latitude 36°00’N / Longitude 006°00’W. With a local variation of 2°NW and a compass deviation of (-6º). Calculate the compass course.
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Correct answer: c) 048º
Why it is correct
True course = 39º. Total correction = −2º − 6º = −8º. Compass = 39º + 8º = 47º. The working gives 47º, and the nearest option is 048º: that is the normal gap from measuring on the chart.
Why the others are not
- a) No correct calculation gives this.
- b) It applies the correction wrongly.
- d) No correct calculation gives this.
How to work it out in the exam
- Add variation and deviation with their signs.
- Compass = true − total correction.
Where this question comes from
- Región de Murcia · 2023 · 1ª convocatoria · PER Tipo 1 · question 42 Official paper · Official answer key
Try it: Navigation calculations
Pending instructor review. Machine translation, not reviewed.