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A HRB = 09:00, navegando al Rumbo verdadero = 080º a 8 nudos de velocidad, obtenemos Marcación al Faro de Punta Carnero = 60º Babor y Marcación al Faro de Punta Camarinal = 140º Babor. Calcular la situación.At 09:00 ship’s time, steering true course 080º at 8 knots, you take relative bearings of Punta Carnero = 60º Port and Punta Camarinal = 140º Port. Calculate your position:

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Correct answer: c) 35º 56.5' N, 005º 29.3' W

Why it is correct

With Rv = 080º and both relative bearings to port: Dv(Carnero) = 080º − 60º = 020º and Dv(Camarinal) = 080º − 140º = 300º. Plotting both bearings from the lights intersects at 35º 56.5′ N, 005º 29.3′ W.

Why the others are not

  • a) Does not match the charted intersection of Dv = 020º to Punta Carnero and Dv = 300º to Punta Camarinal.
  • b) Does not match the charted intersection of Dv = 020º to Punta Carnero and Dv = 300º to Punta Camarinal.
  • d) Does not match the charted intersection of Dv = 020º to Punta Carnero and Dv = 300º to Punta Camarinal.

How to work it out in the exam

  1. Subtract the port relative bearings from the true course: Dv(Carnero) = 020º and Dv(Camarinal) = 300º.
  2. Plot their reciprocals from each light and read the fix: 35º 56.5′ N, 005º 29.3′ W.

Where this question comes from

Try it: Navigation calculations

Pending instructor review. Machine translation, not reviewed.