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Con declinación= −26º 28,1', latitud estimada= 15º 46,0'S, y un ángulo en el Polo= 11º 04,3' (E), el Capitán de yate "Eagle" calcula el valor de la altura estimada de la estrella "Antares" (Ae*) por las fórmulas que resuelven los ángulos del triángulo de posición, así como la diferencia de alturas, teniendo en cuenta una altura verdadera de= 75º 03,6' :With declination −26º 28.1′, DR latitude 15º 46.0′S and a meridian angle of 11º 04.3′ (E), the skipper of the yacht “Eagle” calculates the computed altitude of the star Antares using the position triangle formulas, and the altitude difference, given a true altitude of 75º 03.6′:
Show the answer
Correct answer: c) Computed altitude 75º 08.6′ – altitude difference −5′
Why it is correct
The formula gives 75º 08.6′. Difference = true − computed = 75º 03.6′ − 75º 08.6′ = −5′.
Why the others are not
- a) It does not match the working.
- b) It does not match the working.
- d) Also, the difference does not fit the two altitudes.
How to work it out in the exam
- sin a = sin l sin d + cos l cos d cos P, with south negative.
- Difference = true − computed.
Where this question comes from
- Región de Murcia · 2017 · 2ª convocatoria · CY Tipo 1 · question 16 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.