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El 26 de noviembre del 2021 obtenemos una altura instrumental limbo inferior del sol de 36º25.4´ La elevación de nuestro observador es de 10m, disponemos de una corrección de índice de 1 (-). Queremos hallar la altura verdadera.On 26 November 2021 we obtain a lower-limb Sun sextant altitude of 36º 25.4' with height of eye 10 m and index correction 1' (-). Find the true altitude.

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Correct answer: b) 36º 33.8'

Why it is correct

With ai = 36º 25.4′, subtract Ci = −1.0′ (ao = 36º 24.4′) and dip for 10 m (−5.6′ → aap = 36º 18.8′). Adding the November lower-limb Sun correction at 36º (+15.0′) gives av = 36º 33.8′.

Why the others are not

  • a) Subtracts nearly 2 degrees from the sextant altitude.
  • c) Drops 1 full degree when adding the minutes.
  • d) Implausible value caused by a decimal point error.

How to work it out in the exam

  1. −1.0′ (Ci) − 5.6′ (dip 10 m) + 15.0′ (Sun) = +8.4′ → 36º 33.8′.

Where this question comes from

Try it: Sight reduction

Pending instructor review. Machine translation, not reviewed.