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El día 26 de abril de 2025 al ser HcL= 23:01:00, encontrándonos en situación: l= 40° 36´0´N; = L= 135º 15´E. Se pide calcular la HcG y la Hz.On 26 April 2025 at local civil time (HcL) 23:01:00, in position l = 40° 36.0' N, L = 135º 15' E, calculate the Greenwich civil time (HcG) and zone time (Hz).
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Correct answer: b) HcG = 14h 00m 00s (on 26/04/2025) and Hz = 23h 00m 00s (on 26/04/2025).
Why it is correct
Longitude 135º 15′ E equals 9h 01m 00s east and belongs to zone −9. Thus HcG = 23:01:00 − 09:01:00 = 14:00:00 on 26/04/2025, and Hz = 14:00:00 + 9h = 23:00:00 on the same day.
Why the others are not
- a) Adds longitude in time instead of subtracting it to reach Greenwich.
- c) Adds longitude in time, rolling over into the 27th.
- d) Misconverts 135º 15′ into hours and minutes.
How to work it out in the exam
- 135º = 9h and 15′ = 1m: L(t) = 9h 01m E.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2025 · Convocatoria de abril · CY Test 1 · question 16 Official paper · Official answer key
- Ministerio de Transportes (Madrid) · 2025 · Convocatoria de abril · CY Test 2 · question 18 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.