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El 22 de noviembre de 2025 tomamos altura instrumental del Sol limbo inferior 36º 25,4’, nos encontramos a una altura de 3 metros sobre el nivel del mar y el error de índice del sextante es 0,8’ (-). Se pide calcular la altura verdadera del Sol.On 22 November 2025 the Sun's lower-limb sextant altitude is 36º 25.4’, height of eye is 3 m above sea level, and the sextant index error is 0.8’ (-). Calculate the Sun's true altitude.
Show the answer
Correct answer: c) 36º 36.5’.
Why it is correct
Starting from ai = 36º 25.4′, subtract 0.8′ for index error (ao = 36º 24.6′) and 3.1′ for dip at 3 m (aap = 36º 21.5′). Adding the November lower-limb Sun correction (+15.0′) gives av = 36º 36.5′.
Why the others are not
- a) Stops at the apparent altitude (36º 21.5′) without adding the Sun correction.
- b) Stops at the observed altitude (36º 24.6′) after applying only index error.
- d) Adds dip of the horizon instead of subtracting it.
How to work it out in the exam
- Do not stop at ao (36º 24.6′) or aap (36º 21.5′): add +15.0′ for the Sun's lower limb.
Where this question comes from
- Ministerio de Transportes (Madrid) · 2025 · Convocatoria de noviembre · CY Test 1 · question 12 Official paper · Official answer key
- Ministerio de Transportes (Madrid) · 2025 · Convocatoria de noviembre · CY Test 2 · question 12 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.