Hover or tap underlined Spanish terms to see their translation and exam tip.
El día 15 de marzo de 2025 estamos en situación estimada le = 45º 15’ N y Le: 003 20`E, siendo el Ángulo en el Polo de la estrella Regulus (nº 50) P = 38º 47,8’ y su declinación d= +11º 50,5’.Calcular su azimut náutico (Zn).On 15 March 2025 we are at DR position le = 45º 15’ N and Le: 003 20`E, the Angle at the Pole of the star Regulus (no. 50) being P = 38º 47.8’ and its declination d= +11º 50.5’. Calculate its nautical azimuth (Zn).
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Correct answer: a) Zn = 237.1º
Why it is correct
It comes to 122.9º. The prompt does not give the side, and the key takes it as west: 360º − 122.9º = 237.1º.
Why the others are not
- b) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- tan Z = sin P / (cos l tan d − sin l cos P).
- Body to the E: Z from north. To the W: 360º − Z.
Where this question comes from
- Región de Murcia · 2025 · 1ª convocatoria · CY Tipo 1 · question 15 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.