Hover or tap underlined Spanish terms to see their translation and exam tip.
El día 14 de marzo de 2026, estando en situación de estima l=35º05’N y L=011º00’W, se observa el Sol a su paso por el meridiano superior del lugar con una altura verdadera meridiana av=52º31,2’, siendo la declinación del Sol, d=-2º 24,7’. Calcular la latitud observada.On 14 March 2026, at DR position l=35º05’N and L=011º00’W, the Sun is observed on the upper meridian of the place with a true meridian altitude of 52º31.2’, the Sun’s declination being -2º 24.7’. Calculate the observed latitude.
Show the answer
Correct answer: b) 35º 04.1’N
Why it is correct
z = 37º 28.8′. l = −2º 24.7′ + 37º 28.8′ = 35º 04.1′ N.
Why the others are not
- a) It does not match the working.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- z = 90º − a.
- Facing south: l = d + z, with south d negative. Facing north: l = d − z.
Where this question comes from
- Región de Murcia · 2026 · 1ª convocatoria · CY Tipo 1 · question 14 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.