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A hora civil de Greenwich= 17:43:40, en longitud estimada= 056º 35,0'E y con un horario en Greenwich de la estrella Antares para esa hora= 292º 20,7', calcula el ángulo en el Polo (Pl entre el horario de Antares y la longitud del observadorAt Greenwich civil time 17:43:40, in DR longitude 056º 35.0′E and with a Greenwich hour angle of the star Antares at that time of 292º 20.7′, calculate the meridian angle (P) between the hour angle of Antares and the observer’s longitude.
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Correct answer: b) 11 04.3′E
Why it is correct
Local hour angle = 292º 20.7′ + 56º 35.0′ = 348º 55.7′. It is over 180º, so P = 360º − 348º 55.7′ = 11º 04.3′ east.
Why the others are not
- a) With a local hour angle over 180º, the body is east.
- c) It does not match the working.
- d) It does not match the working.
How to work it out in the exam
- East longitude: add. West longitude: subtract.
- Under 180º: P west. Over 180º: P = 360º − hour angle, east.
Where this question comes from
- Región de Murcia · 2017 · 2ª convocatoria · CY Tipo 1 · question 14 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.