Hover or tap underlined Spanish terms to see their translation and exam tip.
Un buque que navega a rumbo de aguja Ra= 150° en latitud: 25° N, toma en el momento del ocaso del sol, Azimut de aguja Zaʘ= 263°, siendo su declinación D= 15° 47’ S. Se pide calcular la corrección total (CT):A ship on compass course 150° at latitude 25° N takes, at sunset, a compass azimuth of the Sun of 263°, its declination being 15° 47’ S. Calculate the total correction (CT):
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Correct answer: d) CT= -10.5°
Why it is correct
cos Z = sin d / cos l gives 107.5º from north, so at sunset true azimuth = 252.5º. Total correction = 252.5º − 263º = −10.5º.
Why the others are not
- a) It does not match the working.
- b) It does not match the working.
- c) It does not match the working.
How to work it out in the exam
- At sunrise or sunset: cos Z = sin d / cos l.
- Total correction = true azimuth − compass azimuth.
Where this question comes from
- Región de Murcia · 2025 · 3ª convocatoria · CY Tipo 1 · question 15 Official paper · Official answer key
Pending instructor review. Machine translation, not reviewed.